Question

What must be added to 3x ^ 3 + x ^ 2 - 22x + 91 so that the result is exactly divisible by (3x^ 2 +7x-6)?​

Answer 1

Answer:

2x+3

Step-by-step explanation:

Let us divide $\frac{3x^{3} +x^{2} -22x +9 }{3x^{2} +7x -6}$by long division method .

Therefore, the  remainder is −2x−3 that is −(2x+3)

Hence, −(2x+3) must be subtracted from $3x^{3}+x^{2} -22x+9$ so that is (2x+3) must be added to $3x^{3}+x^{2} -22x+9$   so that the resulting polynomial is exactly divisible by $3x^{2} +7x-6$