what must be added to 4-3x+9x^2 to get 3-4x^2-x^3?
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Step-by-step explanation:
let the number to be added be x
9x^2-3x+4 -(-x^3-4x^2+3)=x
9x^2-3x+4+x^3+4x^2-3 = x
x^3+13x^2-3x+1 = x
x^3+13x^2-3x+1 must be added to 4-3x+9x^2 to get 3-4x^2-x^3
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