What must be added to 4x4+2x3-2x2+x-1 so that the resulting polynomial is divisible by x2-2x-3?
class 10 (polynomial )
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Answered by
74
91x + 89 is added to 4x⁴ + 2x³ - 2x² + x - 1 so that the resulting polynomial is divisible by x² - 2x - 3.
Given:
p(x) = 4x⁴ + 2x³ - 2x² + x - 1
g(x) = x² - 2x - 3
Step-by-step explanation:
x² - 2x - 3)4x⁴ + 2x³ - 2x² + x - 1(4x² + 10x + 30
4x⁴ - 8x³ - 12x²
10x³ + 10x² + x - 1
10x³ - 20x² - 30x
30x² + 31x - 1
30x² - 60x - 90
91x + 89
∴ When the polynomial 91x + 89 is added to the polynomial 4x⁴ + 2x³ - 2x² + x - 1 then the added polynomial is completely divisible by x² - 2x - 3.
Answered by
35
So,reminder = -61x+65
And, the quotient = 4x²-6x+22
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