What must be added to (5x³-2x²+3x+7) to get (7x³+7x-5)
Answers
Answered by
2
Answer:
2x³ + 2x² + 4x - 12
Step-by-step explanation:
Let the number be a.
==: a + (5x³-2x²+3x+7) = (7x³+7x-5)
==: a = (7x³+7x-5) - (5x³-2x²+3x+7)
==: a = 7x³ + 7x - 5 - 5x³+ 2x² - 3x - 7
==: a = 2x³ + 2x² + 4x - 12
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Answered by
0
Answer:
2x³+2x²+4x-12
Step-by-step explanation:
let the required number be x
x=(5x³-2x²+3x+7)=(7x³+7x-5)
x=(7x³+7x-5)-(5x³-2x²+3x+7)
x=7x³+7x-5-5x³+2x²-3x-7
x=2x³+2x²+4x-12
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