what must be added to 6x5+5x4+11x3-3x2+x+5 so that it may be exactly divisible by 3x2-2x+4
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4
30+20+33-6+x+5
=88+x/10-2x
=8.8+0.5x
=88+x/10-2x
=8.8+0.5x
pvishal3:
hi
Answered by
2
=82+x=10-2x
if x=2 by trial and error method it exactly divides no
=84/6= remainder is 0
if x=2 by trial and error method it exactly divides no
=84/6= remainder is 0
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