Question

what must be added to 7x^3-3x^2+6x+4 to make the sum of x^3-5x^2-x+1

Answer 1

Step-by-step explanation:

Let the "Interger" or "Equation " be "z", which is added in the Eq (5x^3 – 2x^2 + 6x + 7) to make the sum (x^3 + 3x^2 – x + 1).

A.T.Q.

=)(5x^3 – 2x^2 + 6x + 7) + z = (x^3 + 3x^2 – x + 1)

=) z = (x^3 + 3x^2 – x + 1) - (5x^3 – 2x^2 + 6x + 7)

=) z = x^3 + 3x^2 -x + 1 - 5x^3 + 2x^2 - 6x - 7

=) z = ( x^3 - 5x^3) + ( 3x^2 + 2x^2) + ( -x -6x) + ( 1 - 7)

=) z = - 4x^3 + 5x^2 - 7x - 6

Hence,

If ( - 4x^3 + 5x^2 - 7x - 6) is added to (5x^3 – 2x^2 + 6x + 7). The Sum will be equal to (x^3 + 3x^2 – x + 1).