Question

what must be added to 7x³-3x²+2x+12 to make the sum 8x³+15x²-6x+1 ? ​

Answer 1

Step-by-step explanation:

Let number added br x

then

7x^3-3x^2+2x+12 + x = 8x^3+15x^2-6x+1

then transpose

x = 8x^3+15x2-6x+1 - (7x^3-3x^2+2x+12) [ additive inverse ]

ans = 1x^3+18x^2-8x-11