Math, asked by arshuzaidkhan, 2 months ago

what must be added to 9x^3-6x^2+6x-7 to make the sum -6x^3-3x^2-x+1


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Answers

Answered by AestheticSky
5

let the no. that will be added be x

  • \sf 9x³-6x²+6x-7+x = -6x³-3x²-x+1

  • \sf x = -6x³-3x²-x+1-(9x³-6x²+6x-7)

  • \sf x = -6x³-3x²-x+1-9x³+6x²-6x+7

  • \sf x = -15x³+3x²-7x+8

Verification:-

  • \sf 9x³-6x²+6x-7+(-15x³+3x²-7x+8)

  • \sf 9x³-6x²+6x-7-15x³+3x²-7x+8

  • \sf -6x³-3x²-x+1

hence, the required polynomial is -6x³-3x²-x+1

Answered by mathdude500
4

\large\underline\purple{\bold{Solution :-  }}

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 \longrightarrow \red{ \bf \: Let  \: y  \: will \:  be  \: added.}

 \tt  {9x}^{3} -  {6x}^{2}  + 6x - 7 + \: y =  { - 6x}^{3}  -  {3x}^{2}  - x + 1

 \tt \:  y = { - 6x}^{3}  -  {3x}^{2}  - x + 1 - ({9x}^{3} -  {6x}^{2}  + 6x - 7)

  \tt \: y = { - 6x}^{3}  -  {3x}^{2}  - x + 1 - {9x}^{3}  +   {6x}^{2}   -  6x  +  7

 \boxed{ \red{ \tt \: y =  -  {15x}^{3}  +  {3x}^{2}  - 7x + 8}}

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 \large \boxed{ \pink{ \tt \: Verification :  - }}

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Consider LHS

 \tt \: {9x}^{3} -  \:  {6x}^{2}  +  \: 6x - 7 \:  +  \: y

 \tt \: {9x}^{3} -  {6x}^{2}  + 6x - 7 -  {15x}^{3}  +  {3x}^{2}  - 7x + 8

 \tt \: (9 {x}^{3}  -  {15x}^{3} ) + ( { - 6x}^{2}  +  {3x}^{2} ) + (6x - 7x) + ( - 7 + 8)

 \tt \: { - 6x}^{3}  -  {3x}^{2}  - x + 1

:  \implies  \bf \:  LHS = RHS

 \bf \: Hence, Verified

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 \boxed{ \purple{ \rm \: Hence, \:  -  {15x}^{3}  +  {3x}^{2}  - 7x + 8 \: must \: be \: added}}

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