Question

What must be added to
9x2 +24x +16 to make it a perfect
square?​

Answer 1

Step-by-step explanation:

$9 {x}^{2} + 24x + 16 = 0 \\ = > {(3x)}^{2} + \: 2 \times 3x \times 4 + {4}^{2} = 0 \\ = > {(3x + 4)}^{2} = 0 \\ = > (3x + 4)(3x + 4) = 0$

Answer 2

Step-by-step explanation:

$\bold\red{\underline{\underline{Answer:}}}$

$\bold\green{\underline{\underline{Solution}}}$

$\bold{It's \ already \ a \ perfect \ square}$

$\bold{9x^{2}+24x+16}$

$\bold{9x^{2}+12x+12x+16}$

$\bold{3x(3x+4)+4(3x+4)}$

$\bold{(3x+4)(3x+4)}$

$\bold{(3x+4)^{2}}$