Question

What must be added to each of the number 10,18,22,38 to get the numbers which are in proportion

Answer 1

Answer:

2

Step-by-step explanation:

For the sequence to be proportion, we need to ensure that

term1/term2 = term3/term4 ...

Define x:

Let x be the number that we need to add to each number

Solve x:

Sequence = 10, 18, 22, 38

(term 1 + x) /(term 2 + x) = (term 3 + x) / term 4 + x)

(10 + x) / (18 + x) = (22 + x) / (38 + x)

(10 + x)(38 + x) = (18 + x) (22 + x)

380 + 10x + 38x + x² = 396 + 18x + 22x + x²

380 + 48x + x² = 396 + 40x + x²

48x - 40x = 396 - 380

8x = 16

x = 2

Answer: 2 must be added the numbers.

Answer 2

HEY DEAR ... ✌️

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Here's , Your Answer :-

=) Let the number is added be x .

Given , Sequence = 10 , 18 , 22 , 38 .

So ,

=) 1st term = 10 .
=) 2nd term = 18 .
=) 3rd term = 22 .
=) 4th term = 38 .

We know ,

(term 1 + x) / (term 2 + x) = (term 3 + x) / term 4 + x)

Now , putting the values .

=) (10 + x) / (18 + x) = (22 + x) / (38 + x)

=) (10 + x) (38 + x) = (18 + x) (22 + x)

=) 380 + 10x + 38x + x^2 = 396 + 18x + 22x + x^2

=) 380 + 48x + x^2 = 396 + 40x + x^2

=) 48x - 40x = 396 - 380

=) 8x = 16

=) x = 16/8

=) x = 2. (ans.)

Hence , the number is added should be 2 .

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HOPE , IT HELPS ... ✌️