What must be added to each of the numbers 10,17,24,38 to get the numbers which are in proportion.
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Answered by
16
Let the number added be x.
As the numbers are in proportion,
10+x/17+x=24+x/38+x
= (10+x)(38+x)=(17+x)(24+x)
=380+10x+38x+x^2=408+17x+24x+x^2
=380+48x=408+44x
=48x-44x=408-380
=4x=28
=x=28/4
=x=7
Hope it is helpful.
As the numbers are in proportion,
10+x/17+x=24+x/38+x
= (10+x)(38+x)=(17+x)(24+x)
=380+10x+38x+x^2=408+17x+24x+x^2
=380+48x=408+44x
=48x-44x=408-380
=4x=28
=x=28/4
=x=7
Hope it is helpful.
Answered by
10
This is ur answer....
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