Math, asked by jsn4921, 1 year ago

What must be added to each of the numbers 10,17,24,38to get the numbers which are in proportion ?​

Answers

Answered by mn121
1

Let the number added be x.

According to the question,

(10+x)/(17+x) = (24+x)/(38+x)

=> (10+x)(38+x) = (24+x)(17+x)

=> 380 + 48x + x^2 = 408 + 41x + x^2

=> 380 - 408 + 48x - 41x + x^2 - x^2 = 0

=> -28 + 7x = 0

=> 7x = 28

=> x = 28/7

.•. x = 4

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Answered by Tanu4113
5

Answer:

Ans is 4

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