What must be added to each of the numerator and the denominator of the fraction 2/5 to obtain 2/3?
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Answered by
2
Let the number be = x
One of the number = 2/5
Sum of them = 2/3
x + 2/5 = 2/3
x = 2/3 - 2/5
x = 2(5) - 2(3) / 3(5)
x = 10 - 6 / 15
x = 4 / 15
The fraction that has to be added is 4 / 15
One of the number = 2/5
Sum of them = 2/3
x + 2/5 = 2/3
x = 2/3 - 2/5
x = 2(5) - 2(3) / 3(5)
x = 10 - 6 / 15
x = 4 / 15
The fraction that has to be added is 4 / 15
Answered by
2
Answer:
let the no. be x
2+x/5+x=2/3
by cross multiplication we'll get
3(2+x)= 2(5+x)
6+3x= 10+2x
by transposing the terms
3x-2x=10-6
x=4
Hence, the required number that should be added to the numerator and denominator of the fraction 2/5 to obtain 2/3 is 4
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