Question

what must be added to each term of the ratio 3 ratio 5 so that the new ratio becomes 5/6 please answer

Answer 1

Heya !!!
Here is your answer :-

Given,
Current ratio = 3:5

New or required ratio = 5:6

The question asks us what should be added to the ratio. 3:5 to make it 5:6.

Main Solution :-

Ratio 3:5 can be written as $\frac {3}{5}$

Similarly,
Ratio 5:6 can be written as $\frac{5}{6}$

So we have to find what should be added to $\frac {3}{5}$ to get $\frac{5}{6}$.

Let the required no. be x.

So, the equation framed is :-

=> $\frac {3}{5}$ + x = $\frac{5}{6}$

=> Taking L.C.M on L.H.S , we get

=> $\frac {5x + 3}{5} = \frac{5}{6}$

=> Using transposition to solve for $x$.

=> $5x +3$ = $\frac{25}{6}$

=> [ tex] 5x [/tex] = $\frac{25}{6}$ - 3

=> $5x$ = $\frac{7}{6}$

=> $x$ = $\frac{7}{30}$

So, the required no. to be added is $\frac{7}{30}$.

$\boxed{Hope \ it \ helps \ you.}$

Answer 2

Answer:

Step-by-step explanation:

Solution :-

Let the required number to be added be x.

Then we have:

⇒ (3 + x) : (5 + x) = 5 : 6

⇒ (3 + x)/(5 + x) = 5/6

⇒ 6(3 + x) = 5(5 + x)

⇒ 18 + 6x = 25 + 5x

⇒ (6x - 5x) = (25 - 18

⇒ x = 7.

Hence, the required number is 7.