Question

What must be added to each term of the ratio 5:8 so that the new ratio becomes 3:4?


PLEASE ANSWER THE QUESTION
I HAVE EXAMS TOMORROW
​

Answer 1

Step-by-step explanation:

Let us add x to get the required ratio.

$\therefore \frac{5 + x}{8 + x} = \frac{3}{4} \\ \therefore \: 4(5 + x) = 3(8 + x) \\ \therefore \: 20 + 4x = 24 + 3x \\ \therefore \: 4x - 3x = 24 - 20 \\ \implies \: x = 4$

Thus, 4 should be added to get the required ratio.

Answer 2

Let us add x to get the required ratio.

\begin{gathered}\therefore \frac{5 + x}{8 + x} = \frac{3}{4} \\ \therefore \: 4(5 + x) = 3(8 + x) \\ \therefore \: 20 + 4x = 24 + 3x \\ \therefore \: 4x - 3x = 24 - 20 \\ \implies \: x = 4 \\\end{gathered}

∴

8+x

5+x

=

4

3

∴4(5+x)=3(8+x)

∴20+4x=24+3x

∴4x−3x=24−20

⟹x=4

Thus, 4 should be added to get the required ratio.