What must be added to f(x) = 6x^4 + 8x^3 + 18x^2 +
20x + 5 so that the resulting polynomial is divisible
by g(x) = 3x^2 + 2x + 1?
plz solution bata dena please
Answers
Answered by
18
Answer:
Step-by-step explanation
3x^2+2x+1
3x^2-3x+1x+1
3x(x-1)-1(x-1)
(3x-1) (x-1)
X=1/3;X=1
F(x)=6x^4+8x^3+18x^2+20x+5
F(1)=6(1)^4+8(1)^3+18(1)^2+20(1)+5
6+8+18+20+5
=57.
57 must be added to the given polynomial 6x^4+8x^3+18x^2+20x+5
Answered by
4
Given:
f(x) = 6x^4 + 8x^3 + 18x^2 + 20x + 5
g(x) = 3x^2 + 2x + 1
To find:
What must be added to f(x) = 6x^4 + 8x^3 + 18x^2 + 20x + 5 so that the resulting polynomial is divisible by g(x) = 3x^2 + 2x + 1?
Solution:
We use the relation: dividend = divisor × quotient + remainder
f(x) = g(x) × q(x) + r(x)
Quotient = q(x) =
Remainder = r(x) =
Therefore, must be added to the polynomial f(x) = 6x^4 + 8x^3 + 18x^2 + 20x + 5 so that the resulting polynomial is divisible by g(x) = 3x^2 + 2x + 1.
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