Question

what must be added to sum of 2a²-3a+7-5a²-2a-11 and 3a²+5a-8 to get zero
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Answer 1

Answer:

we add 12 to sum of 2a²-3a+7-5a²-2a-11 and 3a²+5a-8 to get zero

Step-by-step explanation:

2a²-3a+7-5a²-2a-11 + 3a²+5a-8

5a² - 5a² - 5a + 5a - 12

-12

-12 + 12 = 0