Question

what must be added to
${x}^{4} - {x}^{3} + {x}^{2} + x +3$
to obtain
${x}^{4} + {x}^{2} - 1$
​

Answer 1

Answer:

4+x−x^3

Explanation:

Answer 2

Given

$x^{4} -x^{3}+x^{2} +x+3 + Required number = x^{4} +x^{2} -1$

Re arranging terms we get

$Required\ number=x^{4} +x^{2} -1-(x^{4} -x^{3}+x^{2} +x+3)\\\\ = x^{4} +x^{2}-1-x^{4}+x^{3}-x^{2}-x-3\\\\ =x^{4}-x^{4}+x^{2}-x^{2}+x^{3}-3-1\\\\ =x^{3}-3-1\\\\ =x^{3}-4$

Required Answer

$x^{3}-4$

#answerwithquality