Question

what must be added to the number 10, 18, 22 and 38 to get the numbers which in proportion

Answer 1

let the no added be x
Nos=10+x,18+x,22+x,38+x

Since the required nos are in proportion
Product of extremes =Product of means
》(10+x)(38+x)=(18+x)(22+x)
》380+10x+38x+x^2=396+18x+22x+x^2
》380+48x=396+40x(x^2 will cut from both sides)
》380-396=40x-48x
》-16=-8x
》x=2
Hence 2 must be added