what must be added to the number 6,10,14 and 22 so that they are in proportion?
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consider x as no to be added
so (6+x)/(10+x)=(14+x)/(22+x)
(6+x)(22+x)=(14+x)(10+x)
132 +28x +x^2 = 140+24x +x^2
4x = 8
x=2
answer = 2
12:20:28:44
hope it will help you
so (6+x)/(10+x)=(14+x)/(22+x)
(6+x)(22+x)=(14+x)(10+x)
132 +28x +x^2 = 140+24x +x^2
4x = 8
x=2
answer = 2
12:20:28:44
hope it will help you
soumisingh:
Are you sure ki ye hi answer hai. I think ye galat hai
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