Question

What must be added to the numbers 6 10 14 and 22 so that they are in proportion?

Answer 1

Answer:

2

Step-by-step explanation:

let the number to be added be a

6+a = 14+a

10+a 22+a

(6+a)(22+a)=(10+a)(14+a)

132+6a+22a+a^2=140+10a+14a+a^2

132-140+28a-24a+a^2-a^2=0

-8+4a=0

4a=8

a=8/4

therefore a=2