Question

what must be added to the polynomial 2x³-3x²-8x, So that it leaves a remainder 10 when divided by 2x+1​

Answer 1

Answer:

Step-by-step explanation:

+10x

Answer 2

Answer:

2x-1 / 2xcube-3xsq-8x+10

2x-1 /2xcube-xSq -8x+10 (Xsquare+X +X) quotient

2x-1/ 0 2xsq -x+10

2x-1/. 2xsq -x+10

2x-1/ 0 0 + 10

Step-by-step explanation:

10 should be added to the polynomial to get the r=10

Doubt (If 10x be added then it can't factorise by 2x for eg

2x-1/ 10x(quotient 5)

2x-1/ 5x -5

5x-5 which cannot be divided later so 10 is the correct answer.