Question

What must be added to the sum of 6a2 + 5a +1 and 3a2-6 to get0 ?

Answer 1

Step-by-step explanation:

We get, the required result by subtracting

2a3 – a2 + 5a – 6 from –a3 + a2 – a + 1

=(-a3 + a2 – a + 1) – (2a3 – a2 + 5a – 6)

= - a3 + a2 – a + 1 – 2a3 + a2 – 5a + 6

= - a3 – 2a3 + a2 + a2 – a – 5a + 1 + 6

= -3a3 + 2a2 – 6a + 7