What must be added to the sum of x2-4x+7 and 2x2+5x-9 to get 0.
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What must be added to 5x3-2x2+6x+7 to make the
Let y be the "thing" to add to 5x^3 - 2x^2 + 6x +7 to equal x^3 + 3x^2 -x +1:
Therefore:
5x^3 - 2x^2 + 6x +7 + y = x^3 + 3x^2 - x + 1
Step 1: Rearrange equation and solve for y
y = x^3 + 3x^2 - x + 1 - (5x^3 - 2x^2 + 6x +7)
Step 2: Carry out multiplication of -1
y = x^3 + 3x^2 - x + 1 - (5x^3 - 2x^2 + 6x +7)
y = x^3 + 3x^2 - x + 1 - 5x^3 + 2x^2 - 6x - 7
Step 3: Rearrange equation
y = x^3 - 5x^3 + 3x^2 + 2x^2 -x - 6x + 1 -7
Step 4: Simplify equation by
y = (1 - 5)x^3 + (3 + 2)x^2 + (-1 -6)x + (1–7)
y = -4x^3 + 5x^2 - 7x -6
Therefore, if you add -4x^3 + 5x^2 - 7x -6 to 5x^3 - 2x^2 + 6x +7, you'll get x^3 + 3x^2 -x +1.
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your answer is in this photo
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