what must be added to X^3-3x^2-12x+19 so that the result is exactly divisible by x^2+x-6?
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x^3-3x^2-12x+19+y=x^2+x-6
y=x^2+x-6-x^3+3x^2+12x-19
y=4x^2-x^3+13x-25
y=x^2+x-6-x^3+3x^2+12x-19
y=4x^2-x^3+13x-25
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