what must be added to x^3+ 3x-8 to get 3x^3+x^2+6
Answers
Answered by
4
3x^3+x^2+6 - ( x^3 +3x-8)
= 3x^3 + x^2 + 6 - x^3 -3x + 8
= 3x^3-x^3 + x^2- 3x + 6 + 8
= 2x^3 + x^2 - 3x + 14
Thus, 2x^3+x^2-3x +14 must be added to given number to get the required number
= 3x^3 + x^2 + 6 - x^3 -3x + 8
= 3x^3-x^3 + x^2- 3x + 6 + 8
= 2x^3 + x^2 - 3x + 14
Thus, 2x^3+x^2-3x +14 must be added to given number to get the required number
Answered by
0
Answer:
Let the polynomial to be added be p.
∴x 3 +3x−8+p=3x 3 +x 2 +6
∴p=3x 3 +x 2 +6−x 3 −3x+8
∴p=2x 3 +x 2 −3x+14
Step-by-step explanation:
Similar questions