What must be added to x^4+2x^3-2x^2+x-1 so that the resulting polynomial is exactly divisible by x^2+2x-3
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Step-by-step explanation:
f(x) = x^4 + 2x^3 - 2x^2 + x - 1
g(x) = x^2 + 2x - 3
Here we get the remainder -x + 2 when we divide f(x) with g(x)
hence ,
-r(x) must be added to the f(x) to make g(x) exactly divisible by p(x)
-[-x+ 2 ] = x - 2
X-2 should be added
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