what must be added to x cube minus 3 x square - 12 x + 19 so that the result is exactly divisible by X square + X - 6
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Answer:
X² + x -6 ) x³ - 3x² -12x + 19 ( x -4
x³ + x² -6x
--------------------------------
-4x² -6x + 19
-4x²-4x + 24
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-2x - 5
hence ,
x³ - 3x² -12x + 19 = (x² +x - 6)(x - 4) -(2x + 5)
x³ - 3x² -12x + 19 + (2x + 5) = (x² + x - 6)(x - 4)
hence if we add (2x + 5)
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