Question

what must be added to x3-3x2+4x-13 to obtain a polynomial which is exactly divisible by x-3​

Answer 1

Answer:

1

Step-by-step explanation:

Let 'k' be the number to be added.

x3-3x2+4x-13+k

f(3)= 0.

f(3) = 3 cube - 3* 3 sq.+4*3-13+k

0 = 27-27+12-13+k

-1+k = 0

k= 0.

HOPE IT HELPS