Math, asked by ishanjunedkhan, 6 months ago

what must be added to x⁵ - x⁴ + 3x³ + 4x² - 3x - 3 so that the result is exactly divisible by x² + 1 ​

Answers

Answered by Brainlyboy73
4

x {}^{2}  + 1)x {}^{5}  + x {}^{4}  +3x {}^{3}  +  4x {}^{2}  - 3x - 3(x {}^{3}  \\  x {}^{5}   \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 1x {}^{3}  \:  \: \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  - krne \: pr x {}^{5} se \: x {}^{5} cancel \: now \\  +  x {}^{4}  +  \:  \:  \:  \:  \:  \:  2x {}^{3} \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \:  \:  \:   \\  now \: hope \: u \: can \: solve \: this \: question

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