what must be added to
y3 - y2 - 3y - 2 to get y2-5y+6?
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Answer:
y2-5y+6 - y3-y2-3y-2 = 2y2 + 8y - y3 + 6
Step-by-step explanation:
= y2 - 5y + 6 - y3 - y2 - 3y -2
= y2 - 5y + 6 - y3 + y2 + 3y +2
= y2(1 + 1) + y( 5+3) +y3 ( -1) +6
= 2y2 + 8y -y3 + 6
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