Math, asked by dr745465, 6 months ago

What must be added to y³-y²-3y-2 to get y²-5y+6​

Answers

Answered by sjoshi1075
2

Answer:

- y³ + 2y² - 2y + 8

Step-by-step explanation:

Let the number to be found be x,

therefore,

(y³-y²-3y-2) + x = y²-5y +6

So, x = (y²-5y +6) - (y³-y²-3y-2)

x = y²- 5y + 6 - y³+ y²+ 3y + 2

x = - y³+ y² + y² - 5y + 3y + 2 + 6

x = - y³ + 2y² - 2y + 8

Hence, the number that must be added to (y³-y²-3y-2) is (- y³ + 2y² - 2y + 8)

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