What must be added to y³-y²-3y-2 to get y²-5y+6
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Answer:
- y³ + 2y² - 2y + 8
Step-by-step explanation:
Let the number to be found be x,
therefore,
(y³-y²-3y-2) + x = y²-5y +6
So, x = (y²-5y +6) - (y³-y²-3y-2)
x = y²- 5y + 6 - y³+ y²+ 3y + 2
x = - y³+ y² + y² - 5y + 3y + 2 + 6
x = - y³ + 2y² - 2y + 8
Hence, the number that must be added to (y³-y²-3y-2) is (- y³ + 2y² - 2y + 8)
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