Question

What must be added x²-5x+6 to get -x²-2x+3​

Answer 1

SOLUTION:Let, assume that we add, r(x)we know, thatp(x) + r(x) = q(x)where,p(x) = x² + 5x - 6q(x) = x³ - 2x² + 4x - 5substituting these values in formula we got,\bold{ \to p(x) + r(x) = q(x)}→p(x)+r(x)=q(x)\bold{ \to {x}^{2} + 5x - 6+ r(x) = {x}^{3} - 2 {x}^{2} + 4x - 5}→x 2 +5x−6+r(x)=x 3 −2x 2 +4x−5\bold{ \to r(x) = {x}^{3} - 2 {x}^{2} + 4x - 5 -{x}^{2} - 5x + 6}→r(x)=x 3 −2x 2 +4x−5−x 2 −5x+6

simplify it, we get\bold{ \to r(x) = {x}^{3} - 3 {x}^{2} - x + 1 }→r(x)=x 3 −3x 2 −x+1

Hence, x³ - 3x² - x + 1 will be added to x² + 5x - 6 to get x³ - 2x² + 4x - 5.MARK AS BRAINLIEST

Answer 2

Answer:

-x²-7+9

Explanation:-

x²-5x+6

-

-x²-2x+3

--------------------

-x²-7+9