what must be added x³-3x²+4x-13 to obtain a polynomial which is exactly divisible by(x-3)
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Answer:
Step-by-step explanation:
p(3)=3^3-3*3^2+4*3-13
=27-3*9+12-13
=27-27+12-13
=-1
Therefore,-1 should be added to x^3-3x^2+4x-13 to obtain a polynomial which is exactly divisible by x-3
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