Math, asked by marshall6638, 1 month ago

What must be multiple with 64300 to be a perfect cube number?

Answers

Answered by shaheenarshi427
1

Step-by-step explanation:

Prime factorising 6912, we get,

6912=2×2×2×2×2×2×2×2×3×3×3

=2

8

×3

3

.

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2's is 8 and number of 3's is 3.

So we need to multiply another 2 to the factorization to make 6912 a perfect cube.

Hence, the smallest number by which 6912 must be multiplied to obtain a perfect cube is 2.

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