What must be multiple with 64300 to be a perfect cube number?
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Step-by-step explanation:
Prime factorising 6912, we get,
6912=2×2×2×2×2×2×2×2×3×3×3
=2
8
×3
3
.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 2's is 8 and number of 3's is 3.
So we need to multiply another 2 to the factorization to make 6912 a perfect cube.
Hence, the smallest number by which 6912 must be multiplied to obtain a perfect cube is 2.
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