Math, asked by coumoudaramesh, 9 months ago

what must be subracted from 6y³-4y+8 to get 4y³-2y²-y-1 ?​

Answers

Answered by manasvis2005
0

Hey there,

If we assume the reqd answer to be A

Then, 6y^3-4y+8-(A)=4y^3-2y^2-y-1

So, A=2y^3+2y^2-3y+9

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