Math, asked by aadhilalmash, 1 month ago

What must be subracted from each term of the
ratio 49:68 So that it becomes 3:4?

Answers

Answered by sikrishnamoorthy620

0

Answer:

-8

Step-by-step explanation:

Let the number to he subtracted be x.

Ratio = 49-x/68-x

49-x = 3

68-x 4

On cross-multiplication,

4×(49-x) = 3×(68-x)

196 - 4x = 204 - 3x

-4x + 3x = 204 - 196

-x = 8

Therefore x = -8

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