Question

what must be substracted from a^2 +b^2 +c^2-3abc to get 2a^2-b^2-3c^2+abc​

Answer 1

Answer:

-a² + 2b²  + 4c² - 4abc

Step-by-step explanation:

Let N be the expression that must be subtracted from a² + b² + c² - 3abc to get 2a² - b² - 3c² + abc

So, a² + b² + c² - 3abc - N = 2a² - b² - 3c² + abc

⇒ N =  a² + b² + c² - 3abc - (2a² - b² - 3c² + abc)

⇒ N =  a² + b² + c² - 3abc - 2a² + b² + 3c² - abc

⇒ N =  a² - 2a² + b² + b² + c² + 3c² - 3abc  - abc

⇒ N =  -a² + 2b²  + 4c² - 4abc  

So,  -a² + 2b²  + 4c² - 4abc   must be subtracted from a² + b² + c² - 3abc to get 2a² - b² - 3c² + abc .

Answer 2

HEY,ARMY

YOUR ANSWER IS:

LET THE POLYNOMIAL BE "X"

or,(a²+b²+c²-3abc)-x=(2a²-b²-3c²+abc)

or,(a²+b²+c²-3abc)-(2a²-b²-3c²+abc)=x

or,a²+b²+c²-3abc-2a²+b²+3c²-abc=x

or,x=-a²+2b²+4c²-4abc

HOPE IT HELPS YOU A LOT.....

HAVE A GOOD DAY.

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