Question

what must be subtracted a3-4a2+5a-6 to obtain a2-2a+1

Answer 1

Subtracting  a3-4a2+5a-6 from a2-2a+1 gives us -a3+2a-4.

To obtain a2-2a+1 from a3-4a2+5a-6, we need to subtract (a3-4a2+5a-6) from (a2-2a+1).

To do this, we can first reverse the order of the terms in (a3-4a2+5a-6) to match the order of terms in (a2-2a+1), as follows:

a3-4a2+5a-6 = a3 + 0a2 - 4a + 5 - 6

Next, we can add the opposite of each term in (a3-4a2+5a-6) to the corresponding term in (a2-2a+1), as follows:

(a2-2a+1) - (a3-4a2+5a-6) = a2-2a+1 - (a3 + 0a2 - 4a + 5 - 6)

= a2-2a+1 - a3 - 0a2 + 4a - 5 + 6

= -a3 + 2a - 4

Therefore, subtracting a3-4a2+5a-6 from a2-2a+1 gives us -a3+2a-4.

For such more questions on subtraction,

https://brainly.in/question/11294502

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