Question

What must be subtracted from 19x + 2x3
+ 30x - 37 to get 8x4 + 22x3 - 7x - 60 ?(step by step formula)

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Answer 1

Answer:

Hello friend

Step-by-step explanation:

#respectgirls and boys

Your answer is :-

But first take the number as 'x' before finding it!

After then its simple. Here solve it like this:-

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(19x^4 + 2x^3 + 30x – 37) – (8x^4 + 22x^3 – 7x – 60)

(19x^4 + 2x^3 + 30x – 37) – (8x^4 + 22x^3 – 7x – 60)= 19x^4 + 2x^3+ 30x – 37 – 8x^4 – 22x^3 + 7x + 60

(19x^4 + 2x^3 + 30x – 37) – (8x^4 + 22x^3 – 7x – 60)= 19x^4 + 2x^3+ 30x – 37 – 8x^4 – 22x^3 + 7x + 60=19x^4 - 8x^4 + 2x^3 - 22x^3 + 30x + 7x - 37 + 60

(19x^4 + 2x^3 + 30x – 37) – (8x^4 + 22x^3 – 7x – 60)= 19x^4 + 2x^3+ 30x – 37 – 8x^4 – 22x^3 + 7x + 60=19x^4 - 8x^4 + 2x^3 - 22x^3 + 30x + 7x - 37 + 60= 11x^4 – 20x^3 + 37x + 23

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So yeah....

11x^4 – 20x^3 + 37x + 23 Is your answer.

Thanks!

Hope it helps!

Please mark brainliest

Answer 2

Step-by-step explanation:

The required result will be

(19x4 + 2x3 + 30x – 37) – (8x4 + 22x3 – 7x – 60)

= 19x4 + 2x3+ 30x – 37 – 8x4 – 22x3 + 7x + 60

= 11x4 – 20x3 + 37x + 23

Plz Mark me as BRAINLIEST bro