Question

what must be subtracted from 2a²+5b²+3 to get 6-7b²-11a²​

Answer 1

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Answer 2

Answer:

From the question, its understood that we have to subtract 5a

2

−7ab−3b

2

+3a from 3a

2

−5ab−2b

2

−3.

= 3a

2

−5ab−2b

2

−3−(5a

2

−7ab−3b

2

+3a)

= 3a

2

−5ab−2b

2

−3−5a

2

+7ab+3b

2

−3a

= −2a

2

+2ab+b

2

−3a−3