Question

What must be subtracted from 2p2 – pq + 5q2 to get -4p2 + 3pq-2q2 ?​

Answer 1

Given :

subtracted from 2p2 – pq + 5q2 to get -4p2 + 3pq-2q2 ?​$=(2p^{2} -pq+5q^{2})-(-4p^{2}+3pq-2q^{2} )\\=2p^{2} -pq+5q^{2}+4p^{2}-3pq+2q^{2}\\=6p^{2} -4pq+7q^{2}$

Answer 2

Given : 2p²– pq + 5q²    and  -4p² + 3pq-2q²

To Find : What must be subtracted from 2p²– pq + 5q²  to get  -4p² + 3pq-2q²

Solution:

Let say N must be subtracted from 2p²– pq + 5q²  to get  -4p² + 3pq-2q²

=> 2p²– pq + 5q² - N =  -4p² + 3pq-2q²

=> 2p²– pq + 5q² - (-4p² + 3pq-2q²)  = N

=>  2p²– pq + 5q² + 4p² - 3pq + 2q² = N

=> 6p²– 4pq + 7q² = N

Hence  6p²– 4pq + 7q² must be subtracted from 2p²– pq + 5q²  to get  -4p² + 3pq-2q²

Learn More:

x³-2x²-9 ; 5x³+2x+9 Add the given polynomial. - Brainly.in

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