Question

What must be subtracted from 3 a square-6 a b - 3 square - 1 to get 4 square - 7ab - 4 b square-1

Answer 1

please mark it as brainlist

Answer 2

/* There are mistakes in the problem , It may be like this */

$Let \: X = 3a^{2} - 6ab - 3b^{2} - 1 \: and \\Y = 4a^{2} + 7ab - 4b^{2} -1$

$Let \: P \: should \:be \: subtracted \:from \:X\\to \:get \: Y$

$\impies X - P = Y$

$\implies P = Y - X$

$\implies P = 4a^{2} + 7ab - 4b^{2} -1 - ( 3a^{2} - 6ab - 3b^{2} - 1 ) \\= 4a^{2} + 7ab - 4b^{2} -1 - 3a^{2} + 6ab + 3b^{2} + 1 \\= 4a^{2} - 3a^{2}+7ab+6ab-4b^{2}+3b^{2} -1 +1 \\= a^{2}+13ab-b^{2}$

Therefore.,

$\green { a^{2}+13ab-b^{2} } \: is \: subtracted\\ from \: 3a^{2} - 6ab - 3b^{2} - 1\: to \:get \\4a^{2} + 7ab - 4b^{2} -1$

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