Math, asked by sujitk73439gmailcom, 11 months ago

what must be subtracted from 3 x square minus 4 y square minus 5 Z square minus 6 to get 4 x square + 5 y square minus 6z square + 7​

Answers

Answered by pulakmath007
18

SOLUTION

TO DETERMINE

The expression to be subtracted from 3x² - 4y² - 5z² - 6 to get 4x² + 5y² - 6z² + 7

EVALUATION

We have to find the expression to be subtracted from 3x² - 4y² - 5z² - 6 to get 4x² + 5y² - 6z² + 7

So the given two expressions are

3x² - 4y² - 5z² - 6 and 4x² + 5y² - 6z² + 7

Hence the required expression is

= ( 3x² - 4y² - 5z² - 6 ) - ( 4x² + 5y² - 6z² + 7 )

= 3x² - 4y² - 5z² - 6 - 4x² - 5y² + 6z² - 7

= - x² - 9y² + z² - 13

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