Math, asked by fernandesrehaan, 4 months ago

What must be subtracted from 3a^2 - 3b^2 - 1 to get 4a^2 - 7ab - 4b^2 + 1

Answers

Answered by ASC435
0

Answer:

just add both of them and you will get the desired answer for your question.

Answered by jecknzil9
0

Step-by-step explanation:

3a^2 - 3b^2 - 1 - x = 4a^2 - 7ab - 4b^2 - 1

-x = 4a^2 - 3a^2 - 7ab - 4b^2 + 3b^2

-x = a^2 - 7ab - b^2

x = 7ab + b^2 - a^2

therefore 7ab + b^2 - a^2 should be substracted from 3a^2 - 3b^2 - 1 to get 4a^2 - 7ab - 4b^2 - 1

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