Question

what must be subtracted from 3a^2-6ab-3b^2-1 to get 4a^2-7ab-4b^2+1 ?
^ = this is square sign​

Answer 1

Answer:

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Step-by-step explanation:

Let X be subtracted from 3a2−6ab−3b2

Then,

3a2−6ab−3b2−1−X=4a2−7ab−4b2+1

x=3a2−6ab−3b2−1−(4a2−7ab−4b2+1)

x=3a2−6ab−3b2−1−4a2+7ab+4b2−1

x=−a2+ab+b2−2