what must be subtracted from 3a square - 6ab-3b square-1 to get 4a square-7ab-4b square+1
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2
Answer:
Let X be subtracted from 3a
2
−6ab−3b
2
Then,
3a
2
−6ab−3b
2
−1−X=4a
2
−7ab−4b
2
+1
x=3a
2
−6ab−3b
2
−1−(4a
2
−7ab−4b
2
+1)
x=3a
2
−6ab−3b
2
−1−4a
2
+7ab+4b
2
−1
x=−a
2
+ab+b
2
−2
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