Question

what must be Subtracted from 3a2-6ab-3b2-1 to get 4a2-7ab-4ab2+1?​

Answer 1

Let x be subtracted.

Then, (3a−6ab−3b-1)-x= 4a^2 -7ab-4b^2

> 3a^2 -6a^2-3b^2-1 -4a^2 +7ab+ 4b^2=x

> 3a^2 -4a^2-6ab+ 7ab- 3b^2 + 4b^2- 1 = x

> x= ab- a^ 2 + b^2 -1

Hope you understood...

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