Question

What must be subtracted from 3a²-6ab-3b2-1 to get 4a²-7ab-4b + 12​

Answer 1

Answer:

${ - a}^{2} + ab + b - 13$

Step-by-step explanation:

$(3 {a}^{2} - 6ab - 3b - 1) - (4 {a}^{2} - 7ab - 4b + 12) \\ = 3 {a}^{2} - 6ab - 3b - 1 - 4 {a}^{2} + 7ab + 4b - 12 \\ = - {a}^{2} + ab + b - 13$