Math, asked by rekhalata83, 3 months ago

What must be subtracted from 3a²+ab+4b²+3 to get a²+2ab-3b²+6?

Answers

Answered by aditya1154

0

$(3a²+ab+4b²+3) - (a²+2ab-3b²+6) \\ = > 3a²+ab+4b²+3 - a² - 2ab + 3b² - 6 \\ = > 2{a}^{2} - ab + 7 {b}^{2} - 3$

Answered by ishita8496

0

let x must be substracted

3a²+ab+4b²+3 - x = a²+2ab-3b²+6

3a²+ab+4b²+3 -a²-2ab+3b²-6 = x

2a²-ab+7b²-3

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